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Resource Constrained Project Success Plan

July 18, 2020 ☕️ 4 min read

Scheduling tasks in a large project translates to facing a graph optimization challenge:


The Resource-Constrained Project Scheduling Problem is a combinatorial optimization problem that consists of finding a feasible scheduling for a set of nn jobs subject to resource and precedence constraints.

Problem Domain: Network Optimization.

Taks are represented by nodes. Dependencies of tasks on predecessors form a directed graph. Every task has got a duration which is represented by the weight of the directed edges of the graph. Tasks consume limited resources. In order to provide an entry and exit point to the graph we introduce two dummy tasks, x0,xn+1x_0, x_{n+1} with duration 0 and no resource consumption (a.k.a. sentinels).


J: jobs set R: renewable resources set S: set of precedences (edges) between jobs (𝑖,𝑗)J×J T: planning horizon: set of possible processing times for jobs pj processing time of job 𝑗 ur,j amount of resource 𝑟 required for processing job 𝑗cr capacity of renewable resource r \begin{aligned} J: &\text{ jobs set }\\ R: &\text{ renewable resources set }\\ S: &\text{ set of precedences (edges) between jobs $(𝑖, 𝑗) \in J \times J$ }\\ T: &\text{ planning horizon: set of possible processing times for jobs }\\ p_j &\text{ processing time of job 𝑗 }\\ u_{r,j} &\text{ amount of resource 𝑟 required for processing job 𝑗}\\ c_r &\text{ capacity of renewable resource $r$ }\\ \end{aligned}

Example with two resources r1,r2r1, r2 and resource usage uj,ru_{j,r}:



xjt={1,  if job 𝑗 is completed in period t 0,  else x_{jt} = \begin{cases} 1, \ \text{ if job 𝑗 is completed in period t }\\ 0, \ \text{ else }\\ \end{cases}


Minimize the total duration of task completion subject to dependency and resource constraints:

mint(t1)xn+1,ts.t.\min \sum_t (t-1) x_{n+1, t}\\ s.t.\\


Every job incl. end sentinel must be finished latest by end of last time interval:

txj,t=1, jJ{n+1}\sum_t x_{j,t} = 1, \ \forall j \in J \cup \{n+1\}\\

Resource Consumption Constraint:

A job is being processed in period tt if the job is completed in period qq where:

tqt+pjt \le q \le t + p_jjq=tmin{T+1,t+pj}uj,rxj,qcr, t,r\sum_j \sum_{q=t}^{\min{\{T+1, t+p_j\}}} u_{j,r} x_{j,q} \le c_r, \ \forall t, r \\

For another technique to formulate this kind of constraint see Patient Scheduling problem. There we simplify this constraint type with the help of a binary helper data structure.

Sequence constraint:

Job mm must precede job nn. If tm,tnt_m, t_n denote the completion time, then:

tm+pntntj=ttxj,tt_m + p_n \le t_n \\ t_j = \sum_t t x_{j,t}\\ttxj,t+psttxs,t, (j,s)S\sum_t t x_{j,t} + p_s \le \sum_t t x_{s,t} , \ \forall (j,s) \in S \\

Binary Constraint:

xj,t{0,1}x_{j,t} \in \{0,1\}\\


This time the solution of the problem provides two interesting challenges:

1. Solving the MIP problem

The implementation with Pyomo is close to the mathematical problem formulation and therefore straight forward. However, testing and debugging the resource consumption constraint proved to be more involved than expected.

# resource consumption contraint:
def resource_c(model, t, r):
    if t == len(model.T):
        return Constraint.Skip
    return sum(
        model.u[j, r] * model.x[j, q]
        for j in list(model.J)[1:-1]
        for q in range(
            t, min(len(model.T) + 1, t + value(model.p[j]) - 0)
    ) <= model.c[r]

model.resource_c = Constraint(model.T, model.R, rule=resource_c)

Testing the decisions of a MIP solver involves indirect reasoning. There is no debugger which can be attached to the solver in order to set breakpoints (unless you are the solver’s developer, of course).

As a software developer it is probably good advice to follow a path as in Patient Scheduling, where complexity is taken out of the mathematical model and put into helper data structures which can be tested and debugged with tools of the trade.

2. Visualizing the result

Since we have a multi-dimensional result, visualization requires some thought. After all we want to see the temporal sequence of tasks together with a representation of respective resource consumption. Tasks will run in parallel when resource consumption allows for it.

Luckily with mathplotlib we have a Python library which provides all the necessary routines and tools in order to visualize even the most complex data-sets.

I chose to visualize ‘swim lanes’ per resource, where the height of the swim lane represents the resource limit, and the length represents the maximum length if all jobs would have been run sequentially (naive solution).


Our example problem is a relatively small MIP problem and CBC has no problems solving it within a second:

Number of constraints : 97
Number of variables : 420


The optimal solution is more than one third ‘better’ than the naive solution by parallelizing tasks where possible. Hereby the sequence of tasks is respected as well as the limitation of resources. Get more done in the same amount of time.

If you are interested in other MIP problems regarding task scheduling, please check out Task Scheduling, The Book of Mormon and The Book of Mormon II.

always be building, by sysid.

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